javascript
/**
* @param {number[]} nums
* @param {number} target
* @return {number}
*/
var threeSumClosest = function (nums, target) {
let result
let minGap = 0
const len = nums.length
if (nums === null || len < 3) {
return result
}
nums.sort((a, b) => a - b)
if (nums[0] > target) {
result = nums[0] + nums[1] + nums[2]
}
for (let i = 0; i < nums.length - 2; i++) {
let L = i + 1
let R = len - 1
while (L < R) {
let sum = nums[i] + nums[L] + nums[R]
let gap = Math.abs(sum - target)
if (gap === 0) {
result = sum
break
}
if (gap < minGap || minGap === 0) {
minGap = gap
result = sum
}
sum > target ? R-- : L++
}
}
return result
}